And the probability to attack n times is 1/(2)^n , so a chain of infinite attacks is very unlikely. Nothing to discuss here, I guess…

BUT !

Let’s do some more math because I like it

Let’s say you cast it at turn *four*, so it starts attacking *(IF not dealt with before)* on turn *five* where you almost certainly dealt a mean of 3 damages to opponent’s face, *(you smorky)*.

So he’s at *22* and you need *nine extra attacks* from him and *one* from your general

*( your other creatures are dead because your opponent can’t do his math and tought that **IT WASN’T SUCH A BIG THREAT AFTER ALL!!* [And he was right] )

BUT!

Your opponent has some creatures, because I guess you were too busy smorking to clear board, weren’t you?

So let’s say a mean of *three creatures* with a mean of *four health* each

Another *six* attacks to deal with everything, and we have:

1/(2^15)=1/32768= 0,000031%

BUT!

Let’s say you want to ignore creatures and hit only the general *(you smorky)*

You will have to count enemies remaining and the probability to hit just *one* of them, *times* the probability NOT TO HIT THE OTHERS!

So…let’s say *four* total enemies

Each extra shot has a probability of [1/2]*[1/4]*[1-3/4]=1/(2^5)

For *each* shot

To a grand total of

[1/(2^5)^10]=0,0000000000000009 %

Conclusions:

Totally OP

Let me know if I did everything right (even with grammar, not my mothertongue)

Bye folks, when you reach the fourth turn OTK notify me