Duelyst Forums

Drogon meme 101, power to much, over 9k (now with, just maths)

#1

So myself and Kheart wanted to try something interesting, fractal replication on drogon! But then we figured we can do the same thing with flawless reflection, and waddya know?
~EXTREME POWERRRRRR~
Sad we didn’t try it with 3 cryptographer in a turn :frowning: but eitherway its worth it :smiley:

memes
memes.JPG1230×715 177 KB

That’s it
I just wanna c how i can break the game and yet it’s not broken
show me yours for the most power u can get with a friend or in a game (even better)!

edited
with 3 cryptographer in one turn.

memes 2
memes 2.jpg1411×794 225 KB

good luck guessing the no. though xD

7 Likes
#2

Kek kek kek, you are but foolish mortals. Some guy has already gotten Vaath to like 2^200 or something crazy.

2 Likes
#3

@excogitator
’Nuff said.

#4

lol, gonna try it later

#5

image

@excogitator the math god

1 Like
#6

nice jpeg dude, did you remember to turn the flash off?

#7

fixed, so now you look like a doofus haha

1 Like
#8

Howdy! It’s fantastic to find another group of players who want to push the power of Vaath so high!

Unfortunately, breathing the game with large numbers will not come anytime soon. With Zureal, Cryptographer, and Hailstone pursuing, I managed to get a Vaath’s attach over 10^100. However, it is more than likely that the number counter goes as high as 10^300, and I think 9 Cryptographers is the limite since the only way to reduce its cost is Kujata, and it can only lower cost by 1 (everything else can be less we’re to zero). Therefor, the 9 mana cap stops you from playing any more cryptographers and therefore BBSing more than 10 times in one turn.

He only hope is something that lowers Cryptographer’s cost without dealing damage to it, or something to BBS infinitely. With a full board of Dragons, it would take around 30 BBS to reach over 10^300, enough to break the game.

Also, try to beat my record!

(3.56*10^104)

#9

Was this done before or after kraigon?

#10

This was done right after Rise of the Bloodbound

Kraigon barely makes a dent in the bucket. 7 attack per turn is insignificant compared to Drogon’s Doubling potential.

2 Likes
This thread's title has finally been decided on
#11

Considering this reply exists, you’re the one that ends up looking like a doofus. :^>

#12

I think you miss understand. Kraigon +7 will be 7 more for every double. So trip drogon at just 5 attack is 10->20->40. Trip drogon with one kraigon is 12 attack and then 24->48->96. At x^100 I think you see what I mean. Isn’t this what is needed to break the system? Alongside crypt, one or two sustained Kraigon?

#13

The doubling formula is attack*2^x, not attack^x. Before doubling, it does not matter if I add 100 attack to Vaath, it doesn’t even matter if I add 1 million attack to Vaath. That just accounts for 10^2 or 10^6 times more attack in the end. I need to come up with 10^200 times more attack, not something that can be achieved through only Kraigon. The only way to do that is to find more ways to multiply the exponent, either through more Drogon effects, or more BBS triggers.

In fact, I challenge you to get the attack above 10^130 with the Kraigon technique. If you do it, I will craft 10 prismatic Serpenti and post a picture on the forums.

#14

I would try, but I’m too technologically incompetent to install tk’s script.

Other than that I’m not a math guy. I just figured that better base with however many drogons and crypts would just up the numbers bc more numbers.

#15

The point I’m trying to stress here is that if Vaath starts with 1 or 1 million attack, the end result will not be too different on an exponential scale.

Say you start with x attack and it gets doubled 200 times by drogon.

You would get x*2^200
Or y^120

If you start with 1 million x attack and it gets doubled 200 times, you would get

x10^62^200
Or y*10^126

10^120 and 10^126 is not that far on the exponential scale and will get us nowhere when aiming for 10^300

Also, the Serpenti challenge still holds if anyone wants to take me on!

#16

after, decided to get it as high as possible.

#17

hmmmm idk how much is my second one but it looks pretty legit to me

#18

Best Drogon is Mirage Drogon. “Oh don’t mind me, good sir- I’ll have three of those”

#19

Stealing the new Bound Tormentor could do that. (Mindwarper a Nether Summoning or something.)

Some (very crazy) ideas:

Loreweaver to duplicate Fractal Replication.
Replicate Bound Tormentor.
Create duplicate Cryptos.

Loreweaver to duplicate Darkfire Sacrifice (DFS) .
You could clear Crypto space with duplicated DFS instead of Hailstone.

There is a hand limit though. You could replace the Cryptos and DFS, then draw them back.

Use Bound Tormentors to get duplicate Abjudicators.
Get zero cost Rites.
Loreweaver to duplicate zero cost Rites.

Clear the board. (Maybe Plasma Storm.)
Set Drogon field stuff with Sanguinar.
Draw Cryptos, DFS and Rites with Rites.
Execute stuff.

I’m assuming you can replicate a Bound Tormentor properly and that it can be triggered after.
Replacing cards away and duplicating with Loreweaver is not very practicable either.
Assuming perfect draws with Rites.

Assuming Bound Tormentor works you could probably do something with duplicate Baronettes where the buff stays.

1 Like
#20

Darkfire sacrifice and Bound Tormentors sounds like it might just work! I would need some Mogwais and Starhorn instead of Vaath, to get the card draw though.

I’m not sure about sentinels. If I steal them without playing, will they be watchful sentinels, or the transformed ones? Reaper of the 9 moons makes the original unit, but I wonder if Nether Summoning does the same…

Wait! I can use frenzy to Mindlathe a bunch of them! And then evolutionary Apex into Cryptographer! I must test this! Thanks for the idea! I think this one might actually work, but I would need Grincher to pull Mindlathe for Starhorn.

However, this will make it an absolute RNG clown fiesta, since you would need near-perfect draws, and Grincher to pull through.

4 Likes